C Problem Interestin puzzle

Hi chk this code....int i, n = 20; for (i = 0; i < n; i--)printf("-");You have to print '-' 20 times. by adding or removing or replacing onlya single character from the code.There are 3 possible solutions for the above question. Can u get them?

change -- to ++

If u change from -- to ++ then,that wud be changing 2 characters.. whereas it is allowed to add/delete/replace only a single character.

my bad

ok here it is, change i-- to n--, that wasn't so hard man

well I can try, but you have to try also...I'll get started tonight

hi,actually i tried it few days back and got the solutions(2 by me and one by a friend),found it interesting and so posted it here..

yeah, that is one solution and probably the simplest one.But as i told u there are 3 solutions in all. Can u figure out the other two?should take a little more time than the earlier one

Hi,Without changing anything it prints already "-" twenty times and much more. I suppose it has to print exactly twenty times. right?

int i, n = 20;

for (i = 0; i < n; i--)

printf("-");

 

 

You have to print '-' 20 times. by adding or removing or replacing only

a single character from the code.

There are 3 possible solutions for the above question. Can u get them?

<{POST_SNAPBACK}>

1. replace i with n in the for() loop

2. make it -i < n

3. in for() loop init i as 40 (for(i=40;i < 20 ... )

so there :-)

sunilr no.3 is not correct!cse_icons , you sure there's another way!?

yeah, there are 3 solutions all-right...i will post all the solutions in my next reply... got to go now....bye....

hi all,

here are the 3 solutions, in case you still want to give it a try.. dont look at the solutions below:

int i, n = 20; [br]for (i = 0; i < n; n--)[/br]printf("-");

int i, n = 20; [/br]for (i = 0; -i < n; i--)[br]printf("-");

int i, n = 20; [/br]for (i = 0; i + n; i--)[/br]printf("-");

Good Logical solution in third method i like that , thanks