I want to print the variable name not the value of variable. Php Variable Concatenation

[iGuest 3]

I want to print the variable name not the value of variable.Php Variable Concatenation

<?php

$a=1;

$b=2;

$c=$a+$b;

echo("when adding $a and $b, the result should be ". $c);

//it should print when adding $a and $b, the result should be 3

?>

-question by bino

 

REPLY

You have to escape the $ sign using  .Your line will become:-echo("when adding $a and $b, the result should be ". $c);