How To Read Specific Row From Table according where no=xx

For example...a table have 2 columns, 100 rowsfor column i.e. no, nameI want to get corresponding name when no=17How to write this php coding??

An idea could be to Click Here: http://forums.xisto.com/no_longer_exists/
There you find a tutorial about that, just rewrite a little on that script and it will problety work, Hope i Helped

~ Arne-Christian

Not too hard:

 

print "<tr><td>Column 1</td><td>Column 2</td></tr>";$query = mysql_query("SELECT * FROM table");while($getArray = mysql_fetch_array($query)){print "<tr><td>$getArray[number]</td><td>$getArray[name]</td></tr>";}

Note that while{} is an ongoing loop, it will load any number of records

 

wich will display a full list* of each record, showing number and the name attached to it.

 

* To limit the number of results change the query by:

$query = mysql_query("SELECT * FROM table LIMIT 10

the above code would limit the number of results (rows) to 10

 

* To order the number of results change the query by:

$query = mysql_query("SELECT * FROM table ORDER BY number DESC");

the above code would order the list by number descending

 

* To do both:

$query = mysql_query("SELECT * FROM table ORDER BY number DESC LIMIT 10");

any questions ill gladly answer

Not too hard:

 

print "<tr><td>Column 1</td><td>Column 2</td></tr>";$query = mysql_query("SELECT * FROM table");while($getArray = mysql_fetch_array($query)){print "<tr><td>$getArray[number]</td><td>$getArray[name]</td></tr>";}

Note that while{} is an ongoing loop, it will load any number of records

 

wich will display a full list* of each record, showing number and the name attached to it.

 

* To limit the number of results change the query by:

$query = mysql_query("SELECT * FROM table LIMIT 10

the above code would limit the number of results (rows) to 10

 

* To order the number of results change the query by:

$query = mysql_query("SELECT * FROM table ORDER BY number DESC");

the above code would order the list by number descending

 

* To do both:

$query = mysql_query("SELECT * FROM table ORDER BY number DESC LIMIT 10");

any questions ill gladly answer

215958[/snapback]

Your method is good to deal with large data.

Are there any other easy methods to show only 1 record with corresponding no. easily?

Try this code. It might help.

$db = mysql_connect ("localhost", "username", "password");mysql_select_db ("database_name"); $query=mysql_query("SELECT field1,field2 FROM table WHEN no=17");while($row=mysql_fetch_row($query)){     echo $row[0].'<br>'.$row[1];}

Try this code.  It might help.

 

$db = mysql_connect ("localhost", "username", "password");mysql_select_db ("database_name"); $query=mysql_query("SELECT field1,field2 FROM table WHEN no=17");while($row=mysql_fetch_row($query)){     echo $row[0].'<br>'.$row[1];}

216091[/snapback]

thx a lot